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Author: sbrncic
Time: 12/09/03 12:18 PST
This is a reply to message no. 12748 by Badman3k
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Current Topic:
Integral of cot^2(x), the method.
All I can tell you is that the Trig identity:

cot^2(x) = csc^2(x)-1

and the indefinite integral of csc^2(ax) = -cot(ax)/a

therefore:

the integral[cot^2(x)] = integral[csc^2(x)] - integral[1]

which yields your answer of cotx - x
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