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Author: acroduster1
Time: 01/15/04 03:28 PST
This is a reply to message no. 13004 by dfischer
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Current Topic:
Gearing formulas
Care for a right answer?  I'm running very tight on time, so I'll do the one I can do from my head, then I'll tackle the rest later:

For #2:

Say the worm's rotational velocity is 1rpm, the worm wheel's velocity is then 1/40rpm.  At 1rpm, the edge of the worm wheel is moving at 3/4"/minute because pitch indicates how far you move with one revolution.  If you do 1 rpm, the edge moves 3/4" in that minute.

Armed with the rotational velocity of the worm wheel (1/40rpm) and the edge velocity (3/4"/min.) we can calculate the diameter of the wheel.

The formula for radius using edge velocity and rotational velocity is:

v=omega*r, where omega is your rotational velocity.

Put in the numbers and do your units bookkeeping:

3/4"/min = 1/40 rpm * ((2*pi rad/min)/1rpm) * r

Put everything on the left side:

4.775" = r

D = 2r, so D = 9.55",  your answer is a.

A note to gerdb:  stay away from the philosophy books, and pay more attention to your engineering texts...
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