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 Author: acroduster1 Time: 01/15/04 03:28 PST This is a reply to message no. 13004 by dfischer Reply | Original Message | New Topic | List Topics | List Messages on This Topic
 Current Topic:Gearing formulas Care for a right answer?  I'm running very tight on time, so I'll do the one I can do from my head, then I'll tackle the rest later: For #2: Say the worm's rotational velocity is 1rpm, the worm wheel's velocity is then 1/40rpm.  At 1rpm, the edge of the worm wheel is moving at 3/4"/minute because pitch indicates how far you move with one revolution.  If you do 1 rpm, the edge moves 3/4" in that minute. Armed with the rotational velocity of the worm wheel (1/40rpm) and the edge velocity (3/4"/min.) we can calculate the diameter of the wheel. The formula for radius using edge velocity and rotational velocity is: v=omega*r, where omega is your rotational velocity. Put in the numbers and do your units bookkeeping: 3/4"/min = 1/40 rpm * ((2*pi rad/min)/1rpm) * r Put everything on the left side: 4.775" = r D = 2r, so D = 9.55",  your answer is a. A note to gerdb:  stay away from the philosophy books, and pay more attention to your engineering texts...