Glossary » Beams » Simply Supported » Uniformly Distributed Load » Three Equal Spans » Aluminum I Beam » 10.00 × 8.646
For a simply supported beam in three equal spans, we compute the displacement at the middle of the first and the third spans, and the maximum normal stress

occuring at the second and third supports of the beam.
The tabulated data listed in this page are calculated based on the area moment of inertia (
Ixx = 132.09 in
4) for the
10.00 × 8.646 Aluminum I Beam and the typical Young's modulus (
E = 1.015 × 10
7 psi) of Aluminum Alloys. Note that the typical yielding stress

of Aluminum Alloys can range from 4061 to 7.614 × 10
4 psi. The purpose of this page is to give a rough estimation of the load-bearing capacity of this particular beam, rather than a guideline for designing actual building structures. Please check your local building codes for regulatory requirements.
Note: The weight of the beam itself is not included in the calculation.
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